Calculate the volume of concentrated sulphuric acid required to make 1 liter of 0.2N H2SO4. If density of concentrated H2SO4 is 1.83 gm/ml. ?
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We need to make 1 liter of 0.2 N H2SO4.
We know that,
Normality = Basicity of acid X molarity of acid solution
As, Sulphuric acid is a dibasic acid ( H2SO4).
So, basicity of H2SO4 is 2.
0.2 = 2 x molarity
molarity = 0.1 M (molar)
volume = 1 liter
So, number of moles of H2SO4 required= ?
molarity = (moles of H2SO4)/ (liters of solution)
0.1 = x/1
x= 0.1 moles of H2SO4
=> 0.1 moles of H2SO4 are needed.
molar mass of H2SO4 is 1 x 2 + 32 + 4 x 16 => 98 grams per mole.
So, 0.1 moles of H2SO4 is 0.1 x 98 => 9.8 grams of H2SO4.
Density = 1.83 g / mL
mass= 9.8 g
volume =?
d= m / v
1.83 = 9.8/v
v= 9.8/1.83
v =5.355 mL
Hence, 5.355 mL of concentrated sulphuric acid is required.
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