Math, asked by poulamiray1625, 4 months ago

Calculate the volume of cuboid whose dimensions are 3.6 cm, 8.2 cm and 11 cm.

Answers

Answered by Anonymous
0

Volume of cuboid = 3.6 * 8.2 *11 = 324.72 cm^3

Answered by INSIDI0US
1

Step-by-step explanation:

Question :-

  • Calculate the volume of cuboid whose dimensions are 3.6 cm × 8.2 cm × 11 cm.

To Find :-

  • Volume of cuboid.

Solution :-

Given :

  • Length = 3.6 cm
  • Breadth = 8.2 cm
  • Height = 11 cm

By using the formula,

{\sf{\longrightarrow Volume\ of\ cuboid\ =\ l \times b \times h}}

Where,

  • l = length
  • b = breadth
  • h = height

According to the question, by using the formula, we get :

{\sf{\longrightarrow Volume\ of\ cuboid\ =\ l \times b \times h}}

{\sf{\longrightarrow 3.6 \times 8.2 \times 11}}

{\sf{\longrightarrow 324.72\ cm^3}}

\therefore Hence, volume of cuboid is 324.72 cm³.

More To Know :-

\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}

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