Question

Calculate the volume of dry air at STP that occupies 28cm3 at 14 degree Celsius and 750 mmmHg pressure when saturated with water vapour. The vapour pressure of water at 14 degree Celsius is 12 mmHg​

Answer 1

Answer:

May be acc. to my thoughts

Answer 2

Answer:

25.9 cm^3

Explanation:

V1= 28 cm^3                        V2= ?

T1=14 degree celsius           T2= 273 K

  =(273+14) K

  =287 K

P1= (750-12)mm Hg              P2= 760 mm Hg

   = 738 mm Hg

By Gas equation,

P1V1/T1=P2V2/T2

=> 738*28/287 = 760*V2/273

=> V2= 273*738*28/287*760

=> V2=25.86 cm^3

=> V2=25.9 cm^3  (ans)