Question

Calculate the volume of h2 gas produced at stp by 5 moles of zn

Answer 1

zn + 2hcl. =Zncl2 +h2

1 mole of zinc produces =22.4 litres

5 mole of zinc gives =5x22.4 litres

Answer 2

Concept:

If we divide the given volume by the 22.4 at STP then it will give number of moles.

Given:

Number of Moles of Zinc is 5 mol

Find:

Volume of Hydrogen gas produced

Solution:

The correct balanced equation is

Zn + H₂SO₄ ⇒ ZnSO₄ + H₂

If we assume Zinc as limiting reagent

Then 1 mole of zinc is producing 1 mole of Hydrogen Gas

Means 5 mole of zinc will produce 5 mole of Hydrogen Gas

At STP number of moles equals to the volume of gas given divided by 22.4

The number of moles of hydrogen produced at STP = Volume of Hydrogen Produced at STP / 22.4

5 = Volume of Hydrogen Produced at STP / 22.4

Volume of Hydrogen Produced at STP = 5 × 22.4

Volume of Hydrogen Produced at STP = 112 Litres

So to conclude with we can say that 112 Litre of Hydrogen will be produced.

#SPJ3