Question

calculate the volume of H2 liberated at satp when 1.7g of ammonia is decomposed​

Answer 1

Answer:

Simply, the reaction is  

N2+3H2=2NH3

140gN2 means 140/28= 5  mol;

30 g  H 2  means  30/ 2 = 15 mol

From 1 mol of  

N2  2 mol  N H 3  is prepared in perfect presence of  H 2

Hence,  10 mol of  N H 3 will be produced.

We know,1mol of any ideal gas at STP ( 0 ∘ C  and  1 atm ) contains 22.4L of the ideal gas.

Produced ammonia is  224  L .