Question

Calculate the volume of hydrogen has liberated at STP by the reaction og 100g of zinc with solution of H2SO4

Answer 1

Answer :

34. 26L

Explanation:

the reaction of zn with h2so4 is

zn + h2so4 -- znso4 + h2

it is already balanced

so, 1 mole of zinc gives 1 mole of h2

now, n( no. of moles for zinc) = given mass/ gram atomic mass

n = 100/65.38

n = 1. 529

so no. of moles of h2 liberated is 1.529

now we know for every gas( at STP):

              1 mole = 22.4 L

so  volume of h2 in 1.529 mol = 22.4* 1.529

= 34.26 L