Calculate the volume of hydrogen has liberated at STP by the reaction og 100mg of zinc with solution of H2SO4
Answers
Answer- The above question is from the chapter 'Some Basic Concepts of Chemistry'.
Given question: Calculate the volume of hydrogen liberated at STP by the reaction of 100 mg of zinc with solution of H₂SO₄.
(Atomic masses of Zn = 65 u, H = 1 u, S = 32 u and O = 16 u. Volume of any gas at STP is 22.4 litres. )
Answer: Let's write the balanced chemical equation:
Zn + H₂SO₄ → ZnSO₄ + H₂ ↑
According to Stoichiometry, we see that,
1 mole of Zn reacts with 1 mole of H₂SO₄ to produce 1 mole of ZnSO₄ and 1 mole of H₂ gas at STP.
Using mass-volume relationship,
Zn H₂
65/0.1 = 22.4/x
650 × x = 22.4
x = 0.345 litres
= 345 ml
∴ Volume of H₂ gas produced = 0.345 litres or 345 ml.
Hope it helps you.
Please mark me BRAINLIST answer.
