Calculate the volume of N2O produced at a pressure of 200 bar and 25°C when 65g of zinc is dissolved in nitric acid
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Answer:
PV=NRT
200×v=65÷44×0.0821×(227+25)
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Answer:
Explanation:reaction of zinc+ nitric acid
Zn + 4 HNO3 - zn(NO3)2+ 2NO2 + 2H2O
Moles of Zn =65/65 = 1mole
1/1=X/2. //Pv=nrt
220×v=2×0.082×298
V= 0.24l
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