calculate the volume of nitrogen of 7g at 27C and 750 mm pressure
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Given,
Pressure of gas = 750 mm
we know , 1 atm = 760 mm Hg
so, Pressure of gas in atm = 750/760
= 75/76 atm
Temperature = 27° C
=( 27 + 273)K = 300K
wt of nitrogen gas = 7g
mol wt of N2 gas = 28 g/mol
hence, no of mole of gas = 7/28 = 1/4
now, use,
PV = nRT
here,
P = 75/76 atm
n = 1/4 mol
R = 0.082 atm.Lmol-¹.K-¹
T = 300 K
75V/76 = 1/4 × 0.082 × 300
V = 1/4 × 0.082 × 300 × 76/75 L
V = 6.232 L
Pressure of gas = 750 mm
we know , 1 atm = 760 mm Hg
so, Pressure of gas in atm = 750/760
= 75/76 atm
Temperature = 27° C
=( 27 + 273)K = 300K
wt of nitrogen gas = 7g
mol wt of N2 gas = 28 g/mol
hence, no of mole of gas = 7/28 = 1/4
now, use,
PV = nRT
here,
P = 75/76 atm
n = 1/4 mol
R = 0.082 atm.Lmol-¹.K-¹
T = 300 K
75V/76 = 1/4 × 0.082 × 300
V = 1/4 × 0.082 × 300 × 76/75 L
V = 6.232 L
Answered by
1
Given,
Pressure of gas = 750 mm
we know , 1 atm = 760 mm Hg
so, Pressure of gas in atm = 750/760
= 75/76 atm
Temperature = 27° C
=( 27 + 273)K = 300K
wt of nitrogen gas = 7g
mol wt of N2 gas = 28 g/mol
hence, no of mole of gas = 7/28 = 1/4
now, use,
PV = nRT
here,
P = 75/76 atm
n = 1/4 mol
R = 0.082 atm.Lmol-¹.K-¹
T = 300 K
75V/76 = 1/4 × 0.082 × 300
V = 1/4 × 0.082 × 300 × 76/75 L
V = 6.232 L
hope it helps you
Pressure of gas = 750 mm
we know , 1 atm = 760 mm Hg
so, Pressure of gas in atm = 750/760
= 75/76 atm
Temperature = 27° C
=( 27 + 273)K = 300K
wt of nitrogen gas = 7g
mol wt of N2 gas = 28 g/mol
hence, no of mole of gas = 7/28 = 1/4
now, use,
PV = nRT
here,
P = 75/76 atm
n = 1/4 mol
R = 0.082 atm.Lmol-¹.K-¹
T = 300 K
75V/76 = 1/4 × 0.082 × 300
V = 1/4 × 0.082 × 300 × 76/75 L
V = 6.232 L
hope it helps you
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