Question

calculate the volume of o2 at 1atmosphere and 273k , required for the complete combustion of 2.64 litres of c2h2 at 1atmosphere and 273k is​

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Asked on December 27, 2019 by

Saisha Selvi

Calculate the volume of O

2

and 273K required for the complete combustion of 2.64L

of acetylene (C

2

H

2

) at 1 atm and 273K.

2C

2

H

2

(g)+5O

2

(g)⟶4CO

2

(g)+2H

2

O(l)

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ANSWER

Solution:- (C) 6.6 L

Given volume of acetylene =0.25dm

3

=2.64L

Combustion of acetylene (C

2

H

2

)-

2

(acetylene)

C

2

H

2

(g)

+5O

2

(g)

⟶4CO

2

(g)

+2H

2

O

(l)

As we know that volume of 1 mole of gas is 22.4 L.

Amount of oxygen required for the combustion of 44.8 L (2 moles) of acetylene =(5×22.4)L=112L

∴ Amount of oxygen required for the combustion of 2.64 L of methane =

44.8

112

×2.64=6.6L

Hence, 6.6 L of oxygen required for the complete combustion of 2.64 L of acetylen