Question

Calculate the volume of o2 at stp liberated by heating 12.25 gram of kcl o3

Answer 1

The chemical equation for decomposition of KClO3

can be written as:

2KClO3→2KCl+3O2

245 g of KClO3

gives 67.2

L of O2

12.25

g of KClO3

gives 67.2245×12.25

=3.36 L

Answer 2

Answer:

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