Question

Calculate the volume of O2 at stp required to completely burn 24 grams of Mg and also calculate the mass of mg (mg=24 grams, O=16 grams)

Answer 1

Answer:

The chemical equation for the process is:

C+O

2

→CO

2

For the above reaction, 1 mole of O

2

will burn 1 mole of C completely.

In 2.4 g C, number of moles =

12

2.4

=0.2 moles of oxygen is required.

Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L.

Therefore, 0.2 mol O

2

=0.2×22.4 L

=4.48L.

Option D is the correct answer.