Question

Calculate the volume of O2 required for complete combustion of 12.5 dm cube ethane at stp

Answer 1

Dear Student,

◆ Answer -

Volume of O2 required = 43.75 L

● Explanation -

Reaction for combustion of ethane at STP is represented as -

C2H6 + 7/2 O2 --> 2CO2 + 3H2O

From this we can say that, 1 mol of C2H6 reacts with 7/2 mol of O2.

By Avogadro's law, 1 L of C2H6 reacts with 7/2 L of O2.

So now, 12.5 dm^3 of C2H6 will react with 12.5×7/2 = 43.75 dm^3 of O2.

Therefore, 43.75 L of O2 is required for the reaction.

Best luck dear...