Question

calculate the volume of o2 required for complete combustion of 1 litre ch4 gas at NTP.​

Answer 1

Answer:

Number of moles of methane in 4 g sample = 4 g/16 g = 1/4 mole. If 1 mole of CH4 requires 2 moles of O2 for complete combustion. Therefore 1/4 mole of CH4 will requires = 1/4 2 moles of O2 = 0.5 mol of O2 for complete combustion. So 11.2 L of O2 is required for complete combustion of 4 g CH4.

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Explanation:

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Answer 2

Answer:

Number of moles of methane in 4 g sample = 4 g/16 g = 1/4 mole. If 1 mole of CH4 requires 2 moles of O2 for complete combustion. Therefore 1/4 mole of CH4 will requires = 1/4 2 moles of O2 = 0.5 mol of O2