Question

Calculate the volume of O2 required to produce 89.6l H20 at STP

Answer 1

Explanation:

2 moles of H2O gives me 2 moles of H2+1 mole of O2

44.8 litres of H2O =22.4 litre of O2

89.6 litres of H2O =x litre of O2

X=89.6*22.4÷44.8

=44.8 litre of O2

Answer 2

Answer:

2H2 +O2 gives 2H20

22.4 L gives 44.8 L

x L     gives  89.6 L

x = 89.6*22.4/44.8

x=44.8 L

Explanation: