Question

calculate the volume of one mole of any gas at STP and at room temperature(300k) with same pressure 1 atm​

Answer 1

Given

• Temperature₁ = STP = 273 K
• Temperature₂ = 300 K
• Pressure = 1 atm = 1.013 × 10⁵ N/m²

To Find

• Molar Volume

Solution

● Pv = nRT [Ideal Gas Equation]

✭ Moar Volume at T₁ :

→ Pv = nRT

→ 1.013 × 10⁵ × v = 1 × 8.314 × 273

→ 1.013 × 10⁵ × v = 8.314 × 273

→ v = (8.314 × 273)/1.013 × 10⁵

→ v = 0.0224 m³

→ v = 22.4 l

━━━━━━━━━━━━━━━━━━

✭ Molar Volume at T₂ :

→ Pv = nRT

→ 1.013 × 10⁵ × v = 1 × 8.314 × 300

→ 1.013 × 10⁵ × v = 8.314 × 300

→ v = (8.314 × 300)/1.013 × 10⁵

→ v = 0.0247 m³

→ v = 24.7 l