calculate the volume of one mole of any gas at STP and at room temperature(300k) with same pressure 1 atm
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Given
- Temperature₁ = STP = 273 K
- Temperature₂ = 300 K
- Pressure = 1 atm = 1.013 × 10⁵ N/m²
To Find
- Molar Volume
Solution
● Pv = nRT [Ideal Gas Equation]
✭ Moar Volume at T₁ :
→ Pv = nRT
→ 1.013 × 10⁵ × v = 1 × 8.314 × 273
→ 1.013 × 10⁵ × v = 8.314 × 273
→ v = (8.314 × 273)/1.013 × 10⁵
→ v = 0.0224 m³
→ v = 22.4 l
━━━━━━━━━━━━━━━━━━
✭ Molar Volume at T₂ :
→ Pv = nRT
→ 1.013 × 10⁵ × v = 1 × 8.314 × 300
→ 1.013 × 10⁵ × v = 8.314 × 300
→ v = (8.314 × 300)/1.013 × 10⁵
→ v = 0.0247 m³
→ v = 24.7 l
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