Question

Calculate the volume of oxygen at STP that would be required to convert 5.2L of carbon monoxide to carbon dioxide? [hint: 2CO +1/2 O2 --- CO2 ]

Answer 1

2CO+1/2O2----CO2

2dm^3 of carbon requires 0.5dm^3 of O2

5.2dm^3 of carbon will require 0.5/2×5.2 of O2
=1.3dm^3 of O2

Answer 2

Answer: The volume of oxygen required will be 1.3 L.

Explanation:

The chemical equation for the formation of carbon dioxide from carbon monoxide follows:

$2CO+\frac{1}{2}O_2\rightarrow CO_2$

At STP:

1 mole of a gas occupies 22.4 L of volume.

So, 2 moles of carbon monoxide will occupy $2\times 22.4=44.8L$ of volume.

And, $\frac{1}{2}$ moles of oxygen will occupy $\frac{1}{2}\times 22.4=11.2L$ of volume.

By Stoichiometry of the reaction:

44.8 L of carbon monoxide gas reacts with 11.2 L of oxygen gas.

So, 5.2 L of carbon monoxide gas will react with = $\frac{44.8}{11.2}\times 5.2=1.3L$ of oxygen gas.

Hence, the volume of oxygen required will be 1.3 L.