Chemistry, asked by akshat204, 4 months ago

Calculate the volume of oxygen gas that can be obtained at 700 mm and 27ºC by strongly

heating 20 gm of potassium chlorate.

Answers

Answered by manas7083

1

Volume of oxygen at STP which will be obtained by the action of heat on 20 gm of KClO 3

Volume of Oxygen obtained=

$3 \times 22.4 \times \frac{20}{122.5} \times 2 = 5.846 L$

$bts (◍•ᴗ•◍)❤ exo$

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