Calculate the volume of oxygen obtained at STP by heating 24.52g KCLO3
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Answer:
Explanation:
The chemical equation for decomposition of KClO3
can be written as:
2KClO3→2KCl+3O2
245 g of KClO3
gives 67.2
L of O2
12.25
g of KClO3
gives 67.2245×12.25
=3.36 L
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