Question

Calculate the volume of oxygen required fir complete combustion of 1 liter of CH4 at NTP

Answer 1

1 L of CH4 has 1/22.4 moles of CH4

CH4 + 2O2 = CO2 +2H2O

16 g of methane requires 64g of oxygen

1 mole of CH4 requires 2 moles of O2

1/22.4 mole of CH4 requires 2/22.4×22.4 L of O2

=2L of O2