calculate the volume of oxygen required for complete combustion of 0.25 mole of methane at STP
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Answered by
150
Hi thank you for asking the question
Methane is represented by CH4 and a=have moleccular mass of 22.4
when methane is burned following reaction takes place
CH4 + 2O2:::::> CO2 + 2H20 '
In this reaction one mole of methane needs two moles of oxygen to be completely burned
for 0.25 moles we can calculate as;
=0.25*22.4*2
=11.2 Liters
hope this answer helped you
If it did kindly mark the answer as brainliest. Thanks
Methane is represented by CH4 and a=have moleccular mass of 22.4
when methane is burned following reaction takes place
CH4 + 2O2:::::> CO2 + 2H20 '
In this reaction one mole of methane needs two moles of oxygen to be completely burned
for 0.25 moles we can calculate as;
=0.25*22.4*2
=11.2 Liters
hope this answer helped you
If it did kindly mark the answer as brainliest. Thanks
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