calculate the volume of oxygen required for complete combusion of 0.25 mole of methane at stp
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CH4 + 2O2 = CO2 + 2 H2O
From the equation , 0.25 moles of methane need 0.5 moles of oxygen.
1mole of oxygen at stp occupies a volume of 22.4 litres
o.5 moles of oxygen will have a volume = 0.5 x 22.4 = 11.2 litres
From the equation , 0.25 moles of methane need 0.5 moles of oxygen.
1mole of oxygen at stp occupies a volume of 22.4 litres
o.5 moles of oxygen will have a volume = 0.5 x 22.4 = 11.2 litres
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