Calculate the volume of oxygen required for complete combustion of 20cm3 of ethane (C2H2)
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If you don't know the equation equation is
2C2H2 + 5O2=4CO2 + 2H20. According to the gay lussac's law under the same conditions of temperature and pressure gases occupy the same volume at the product and reactant side.
2 mole of ethyne gas occupies 20 cm cube of volume show one mole of ethyne gas occupies 10 centimetre cube volume.
So 5 moles of oxygen occupies 20 x 5 that is 100 cm cube of volume.
Done. Hope it helps
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