calculate the volume of oxygen required for the complete combustion of 50ml of methane. explain the steps?
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Answer:
I am giving you hint and you shortout fastly
Explanation:
22.4 L of the Ethene requires 3 x 22.4 L of Oxygen for combustion.
.: 20 mL of the Ethane requires 3 × 10³ × 20 mL
= 60 x 10³ ml
= 60 L of Oxygen for combustion.
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