calculate the volume of oxygen required for the complete complete combination of two 0.25 dm3 of Methane at STP
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CH4 +2 O2-------------> CO2 + 2 H2O
No of moles of CH4= 0.25/22.4 =0.01 moles ( 1 dm^3= 1 liter)
1 mole of CH4------->2 moles of O2
0.01 moles------------------?
= 0.02*22.4 liters= 0.448 liters or 0.448 dm^3
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