Question

calculate the volume of oxygen required to burn 500 cm3 of methane​

Answer 1

Answer:

ANSWER

Given volume of methane =0.25dm

3

=0.25L

Combustion of methane (CH

4

)-

(methane)

CH

4

+2O

2

⟶CO

2

+2H

2

O

As we know that volume of 1 mole of gas is 22.4 L.

Amount of oxygen required for the combustion of 22.4 L of methane =(2×22.4)L=44.8L

∴ Amount of oxygen required for the combustion of 0.25 L of methane =

22.4

44.8

×0.25=0.5L

Hence, 0.5 L of oxygen required for the complete combustion of 0.25dm

3

of methane.