calculate the volume of oxygen required to burn 500 ml of ethene gas at stp
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Answer:
We have
C
2
H
4
+3O
2
→2CO
2
+2H
2
O
At STP we have
volume of 1 mole of gas = 22400 ml
so, moles of ethene in 20 ml of volume =
22400
1
∗20=0.00089moles
for, 1 mole of ethene we require 3 mole of oxygen
so, for 0.00089 mole of ethene we require oxygen = 0.00089×3=0.00267mole
hence, volume of oxygen require = 22400×0.00267=60ml
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