Calculate the volume of oxygen rewired for the complte combustion of 50ml methane
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2C2H2+5O2→4CO2+2H2O2C2H2+5O2→4CO2+2H2O
By Gay-Lussac’s Law of combining volumes,
52×40=10052×40=100 mL of O2O2 will be required.
By similar calculations, we get,
8080 mL of CO2CO2
and 4040 mL of H2OH2O (in the gaseous state)
By Gay-Lussac’s Law of combining volumes,
52×40=10052×40=100 mL of O2O2 will be required.
By similar calculations, we get,
8080 mL of CO2CO2
and 4040 mL of H2OH2O (in the gaseous state)
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