Question

Calculate the volume of water added to solution obtained by diluting 250 ml 2 M HNO3 to 0.25 M.​

Answer 1

Answer : No. of moles of 0.6M HCl = 0.15

No. of moles of 0.2M HCl = 0.15

let V be the volume(in ml) of the 0.25M solution. No of moles present = 0.15+0.15 = 0.3

0.3*1000/v(ml) = 0.25 M

v = 1.2 lit.

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