Calculate the volume of water that must be added to 15 ml of 0.600 m hcl to make 0.100 m hcl
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This means that if you know how many moles of solute you have in the target solution, you also know how many moles of solute were present in the stock solution sample.
Use the molarity and volume of the target solution to determine how many moles of hydrochloric acid, HCl, you need in that solution
c=nV⇒n=c⋅V
nHCl=0.10 M⋅500⋅10−3L=0.050 moles HCl
Now the question is - what volume of stock solution would contain this many moles of hydrochloric acid?
c=nV⇒V=nc
Vstock=0.050moles12molesL=0.0041667 L
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