Physics, asked by shubhsandhyasd, 8 months ago

Calculate the volume of wood of mass 6000 kg if the density of wood is 0.8 g cm-3.

AND

A piece of wood of mass 150 g has a volume of 200 cm3. Calculate the density of wood in:
(a) C.G.S. unit
(b) S.I. unit

pls answer both the parts

Answers

Answered by BrainlyConqueror0901
18

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Volume=7500000\:cm^{3}}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt:  \implies Mass \: of \: wood(m) = 6000 \: kg \\  \\ \tt:  \implies Density \: of \: wood (\rho)=  0.8 \: g/ cm^{3}  \\  \\   \red{\underline \bold{to \: find :}} \\  \tt: \implies Volume \: of \: wood = ?

• According to given question :

 \bold{As \: we \: know \: that} \\  \tt:  \implies Density =  \frac{Mass}{Volume}  \\  \\\tt:  \implies 0.0008 =  \frac{6000}{Volume}  \\  \\ \tt:  \implies Volume =  \frac{6000}{0.0008}  \\  \\  \green{\tt:  \implies Volume  = 7500000 \:  {cm}^{3} }

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Density=0.75\:g/cm^{3}}}}

\green{\tt{\therefore{Density=750\:kg/m^{3}}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt:  \implies Mass \: of \: wood(m) = 150\: g \\  \\ \tt:  \implies Volume \: of \: wood(V)  = 200\: cm^{3}  \\  \\   \red{\underline \bold{To \: Find :}} \\  \tt: \implies Density\: of \: wood(\rho)=?

• According to given question :

  \bold{As \: we \: know \: that} \\  \tt:  \implies Density =  \frac{Mass}{Volume}  \\  \\\tt:  \implies Density =  \frac{150}{200}  \\  \\ \green{\tt:  \implies Density =  0.75 \: g {/cm}^{3}}  \\  \\ \green{\tt:  \implies Density =  750 \: kg {/ m}^{3}}

Answered by Anonymous
92

1st Question

 \bf{ \red{ \underline{ \underline{Answer}}}}

 \tt{ \pink{Volume = 7500000/ {cm}^{3}}}

\large{\sf{\red{\underline{Solution :}}}}

\tt{\orange{Density= 0.8\:g/{cm}^{3}}}

\tt{\green{Mass=6000\:kg=600000\:g}}

\tt{\blue{Density={\large\frac{Mass}{Volume}}}}

\tt{\red{\implies 0.8={\large\frac{6000000}{V}}}}

\tt{\pink{\implies v=7500000 \: /{cm}{3}}}

\tt{\purple{\boxed{\underline{7.5\: /{m}{3}}}}}

2nd Question

 \bf{ \red{ \underline{ \underline{Answer}}}}

 \tt{ \pink{C.G.S \: unit  density = 0.75 \: g/ {m}^{3}}}

\tt{ \pink{S.I\: unit \: density = 750 \: kg/ {cm}^{3} }}

\large{\sf{\red{\underline{Solution :}}}}

a) C.G.S unit (g/cm³)

 \tt{\blue{Density  =  {\large \frac{150 \: g}{200 {cm}^{3} }}} }

 \tt{\purple{\boxed{\underline{Density = 0.75 \: g/ {cm}^{3}}}}}

b) S.I unit (kg/m³)

 \tt{\orange{Mass = 150 \: g  = 150 \times  {10}^{ - 3} \: kg}}

 \tt{\green{Volume = 200 \:  {cm}^{3}  = 200 \times  {10}^{ - 6}  \:  {m}^{2}}}

 \tt{\pink{Density =  \frac{Mass}{Volume}  = \frac{150 \times  {10}^{ - 3} }{200 \times  {10}^{ - 6} }}}

 \tt{ \purple{\boxed{\underline{Density = 750 \: kg/ {m}^{3} }}}}


BrainlyConqueror0901: well done : )
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