Question

calculate the volume present in 40g of aluminium chloride class 11 question​

Answer 1

Answer:

Molar mass of alcl3 = 27 + 3×35.5 = 133.5

no. of moles = 40 / 133.5

= 0.299

= 0.3 mol (approx)

now we know that

1 mol AlCl3 = 22.4 L at STP

therefore

0.3 mol = 22.4 × 0.3 L at STP

= 6.72 L