Question

calculate the wave length of radiation emitted with a frequency of 1,200KHz(c=3.0×108m/s​

Answer 1

Explanation:

v = 1200 x 10³ Hz

c= 3.0 x 10⁸ m/s

wave length = v/ c

= (1200 x 10³)/(3 x 10⁸)

= 400x 10^-5

= 4 x 10^-3 m

Answer 2

Correct Question :

Calculate the wave length of radiation emitted with a frequency of 1,200KHz. (c = 3.0×10⁸ m/s)

Given :

• Frequency of the emitted radiation = 1,200 KHz
• Velocity of light (c) = 3.0 × 10⁸ m/s

To Find :

• The wavelength of the emitted radiation

Solution :

The relation between frequency , wavelength and velocity of light is given by ;

$\\ \star \: {\boxed{\purple{\sf{ \upsilon = \frac{c}{ \lambda} }}}}$

Here ,

• υ is frequency
• c is velocity of light
• λ is wavelength

We have ,

• υ = 1200 KHz = 1200 × 10³ Hz = 1200000 Hz = 1200000 s⁻¹
• c = 3 × 10⁸ m/s

Substituting the values we have ;

$\\ : \implies \sf \: 1200000 \: {s}^{ - 1} = \frac{3 \times {10}^{8} \: m {s}^{ - 1} }{ \lambda}$

$\\ : \implies \sf \: 12 \times {10}^{5} \: {s}^{ - 1} = \frac{3 \times {10}^{8} \: m{s}^{ - 1} }{ \lambda}$

$\\ : \implies \sf \: 12 \times {10}^{5} \: {s}^{ - 1} \times \lambda = 3 \times {10}^{8} \: m {s}^{ - 1}$

$\\ : \implies \sf \lambda = \frac{3 \times {10}^{8} \: m {s}^{ - 1} }{12 \times {10}^{5} \: {s}^{ - 1} }$

$\\ : \implies \sf \lambda = 0.25 \times {10}^{3} \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{ \lambda = 250 \: m}}}}} \: \bigstar$

Hence ,

• The wavelength of the emitted radiation is 250 m.