calculate the wave length of second line of Lyman series in hydrogen spectr. ( Given Rh= 1.09737 cm-1)
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1/¥=Rh{1/1²-1/2²}
where¥ is wavelength
or 1/¥=Rh{3/4}
or¥=4/3Rh
we know that 2nd line of lyman is balmer
for balmer n=2
where¥ is wavelength
or 1/¥=Rh{3/4}
or¥=4/3Rh
we know that 2nd line of lyman is balmer
for balmer n=2
Taekwondo1:
what is ¥
it is wavelength
ok thanks
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