Question

Calculate the wave length of the radiation emitted with a frequency of 1,200kHz
(c=3.0×10°8)​

Answer 1

Answer:

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Explanation:

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Answer 2

Explanation:

Correct Question :

Calculate the wave length of radiation emitted with a frequency of 1,200KHz. (c = 3.0×10⁸ m/s)

Given :

Frequency of the emitted radiation = 1,200 KHz

Velocity of light (c) = 3.0 × 10⁸ m/s

To Find :

The wavelength of the emitted radiation

Solution :

The relation between frequency , wavelength and velocity of light is given by ;

\begin{gathered} \\ \star \: {\boxed{\purple{\sf{ \upsilon = \frac{c}{ \lambda} }}}} \\ \\ \end{gathered}

⋆

υ=

λ

c

Here ,

υ is frequency

c is velocity of light

λ is wavelength

We have ,

υ = 1200 KHz = 1200 × 10³ Hz = 1200000 Hz = 1200000 s⁻¹

c = 3 × 10⁸ m/s

Substituting the values we have ;

\begin{gathered} \\ : \implies \sf \: 1200000 \: {s}^{ - 1} = \frac{3 \times {10}^{8} \: m {s}^{ - 1} }{ \lambda} \\ \\ \end{gathered}

:⟹1200000s

−1

=

λ

3×10

8

ms

−1

\begin{gathered} \\ : \implies \sf \: 12 \times {10}^{5} \: {s}^{ - 1} = \frac{3 \times {10}^{8} \: m{s}^{ - 1} }{ \lambda} \\ \\ \end{gathered}

:⟹12×10

5

s

−1

=

λ

3×10

8

ms

−1

\begin{gathered} \\ : \implies \sf \: 12 \times {10}^{5} \: {s}^{ - 1} \times \lambda = 3 \times {10}^{8} \: m {s}^{ - 1} \\ \\ \end{gathered}

:⟹12×10

5

s

−1

×λ=3×10

8

ms

−1

\begin{gathered} \\ : \implies \sf \lambda = \frac{3 \times {10}^{8} \: m {s}^{ - 1} }{12 \times {10}^{5} \: {s}^{ - 1} } \\ \\ \end{gathered}

:⟹λ=

12×10

5

s

−1

3×10

8

ms

−1

\begin{gathered} \\ : \implies \sf \lambda = 0.25 \times {10}^{3} \: m \\ \\ \end{gathered}

:⟹λ=0.25×10

3

m

\begin{gathered} \\ : \implies{\underline{\boxed{\pink{\mathfrak{ \lambda = 250 \: m}}}}} \: \bigstar \\ \\ \end{gathered}

:⟹

λ=250m

★

Hence ,

The wavelength of the emitted radiation is 250 m.