Question

Calculate the wave number for the longest wave length transition in the ''Paschen Series'' of hydrogen atom.

Answer 1

Answer:

The class Short_long_word finds and displays the shortest and the longest word

in a sentence.

*/

 

import java.io.*;

class Short_long_word

{

public static void main(String args[])throws IOException

    {

        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

        System.out.print("Enter any sentence : "); //inputting the sentence

        String s=br.readLine();

 

        s=s+" "; //adding a space at the end, to extract the last word also

        int len=s.length(); //finding the length of the sentence

        String x="",maxw="",minw="";

        char ch;

        int p,maxl=0,minl=len;

 

        for(int i=0;i<len;i++)

        {

            ch=s.charAt(i); //extracting characters of the string one at a time

            if(ch!=' ')

            {

                x=x+ch; //adding characters to form word if character is not space

            }Longest wavelength means minimum energy.

So you need to know the work function of

sodium for the calculation as work function is the minimum energy to remove a photoelectron from a metal and varies as the substance changes.

After you know the value of work function in Joules then equate it with hc/lambda as we need the wavelength for the minimum energy.

Now calculate the lambda and that will be your answer.

Explanation: