calculate the wave number of line associated with the transition in Balmer series when the electron moves to n=4 orbit
Attachments:
Answers
Answered by
11
we are given that,
Initial orbit of electron = ni = 4
Final orbit of electron = nf = 2.
Also we know that,
Speed of electromagnetic waves = c = 3 × 108 m/s
Planck’s constant = h = 6.63 × 10−34 Js.
We want to calculate the frequency, wavelength and energy of the emitted photon,
when the atom makes a transition from ni = 4 to nf = 2.
Frequency of the emitted photon can be calculated by using the equation,
E = hf, ⇒ f =
E
h
.
Let’s at first calculate E by using the following relation,
E = −13.6
1
n
2
f
−
1
n
2
i
eV
= −13.6
1
2
2
−
1
4
2
eV
= −13.6
1
4
−
1
16
eV
= −13.6 ×
3
16
eV
= 2.55 eV.
Thus frequency of photon will be,
f =
E
h
=
2.55 eV
6.63 × 10−34 Js
=
2.55 × 1.6 × 10−19 J
6.63 × 10−34 Js
= 6.15 × 1014 Hz.
anshbot:
i did not understand but thank you.
NO PROB
Similar questions