Question

Calculate the wave number of the first line in the balmer series

Answer 1

Ans: As we know the energy of constant state for hydrogen species like Li^+2 or He^+ are multiple of integral type of Z^2 times the energy of hydrogen atom in stationary form
Hence the wave number of first line of ion = 3^2 * 15200 / cm 
= 9 * 15200 / cm = 136800 / cm
Hope this answer suffice your question

Answer 2

Wave number of first line in the balmer series =
$r \times ( {n}^{ - 2}-{ (n + 1)}^{ - 2})$
r=Rydberg constant=109677 per m. n=2 and (n+1)=3.
=> 109677×(1/4-1/9)=>109677×5/36 =15232.9 m approximately .Hope it helps you . Rydberg constant value is 109677 per m .