Question

Calculate the wavelength and energy of radiation emitted for the electronic transition from infinity to stationary stqte of hydrogen atom

Answer 1

Answer:wavelength is 951.5angstrom

Energy is 13.6ev. Or21.6 10^-19

Explanation:

1Â=10^-10metre

Answer 2

Answer:

0.08726*10^-20 J

Explanation:

According to Rydberg equation,

1λ = 109678(1n1^2−1n2^2)

Here n1 = 5, n2 = ∞

Therefore,

1/λ= 109678(1/5^2−1/∞^2)

1/λ= 10967825/25

or λ = 222.793×10^−6m

Now,

Energy is given as,

E = hc/λ

E = 6.63×10^−34×3×10^/8227.93×10^−6

    = 0.08726×10−20J

HOPE IT WILL HELP U !!!!