Question

calculate the wavelength and energy of radiation emitted for the electronic tranition from infinity to stationary state one of the hydrogen atom ( R = 1.09678 × 10^7 m^-1 ) .​

Answer 1

Explanation:

λ

1

=R[

n

1

2

1

−

n

2

2

1

]

n

1

=1 and n

2

=∞

λ

1

=R[

1

2

1

−

(∞)

2

1

]=R

or λ=

R

1

=

1.09678×10

7

1

=9.11×10

−8

m

We know that,

E=hv=h⋅

λ

c

=6.6256×10

−34

×

9.11×10

−8

2.9979×10

8

=2.17×10 −18