Question

Calculate the wavelength and Energy of radiation emitted for the electronic transition from n=5 to n=1 of the hydrogen atom. ​

Answer 1

Answer:

ANSWER

λ

1

=R[

n

1

2

1

−

n

2

2

1

]

n

1

=1 and n

2

=∞

λ

1

=R[

1

2

1

−

(∞)

2

1

]=R

or λ=

R

1

=

1.09678×10

7

1

=9.11×10

−8

m

We know that,

E=hv=h⋅

λ

c

=6.6256×10

−34

×

9.11×10

−8

2.9979×10

8

=2.17×10

−18

J.

Explanation:

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