Question

calculate the wavelength and energy of the photon emitted by an electron in making transition from n=10 state to ground state of a hydrogen atom
please answer it...​

Answer 1

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$\begin{gathered}\sf e = 2.18 \times {10}^{ - 18} ( \frac{1}{n {1}^{2} } - \frac{1}{ {n2}^{2} } ) \\ = 2.18 \times {10}^{ - 18} ( \frac{1}{{1}^{2} } - \frac{1}{ {2}^{2} } ) \\ = 2.18 \times {10}^{ - 18} ( \frac{3}{4} ) \\ = \frac{6.54\times \: {10}^{ - 18} }{4} \\ = 1.635 \times {10}^{ - 18} j\end{gathered}$