Question

Calculate the wavelength and energy of the radiation emitted for the electronic transition from fourth orbit to stationary state 1 of He+ ion.

RH=1 × 107 m-1
Plank's Constant (h) = 6.63 × 10-34 J-s Solution

Answer 1

Answer:

λ

1

= R [

n

1

2

1

-

n

2

2

1

]

= 109678 cm

−1

[

1

2

1

-

∞

2

1

]

= 109678 cm

−1

λ =

109678cm

−1

1

= 9.118 × 10

−6

cm

E =

λ

hc

=

9.118×10

−8

6.62×10

−34

×3

= 2.178 × 10

18

J

Answer 2

Answer:

2.178 × 10 ^18× 10

18

J

λ

1

= R [

n

1

2

1

-

n

2

2

1

]

= 109678 cm

−1

[

1

2

1

-

∞

2

1

]

= 109678 cm

−1

λ =

109678cm

−1

1

= 9.118 × 10

−6

cm

E =

λ

hc

=

9.118×10

−8

6.62×10

−34

×3

= 2.178 × 10

18

J