Chemistry, asked by shailyrajat2627, 1 year ago

Calculate the wavelength and frequency of limiting line of Lyman series.

Answers

Answered by VarshithAyella
23
Here's The Answer
I Did Caluclate
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Answered by hemakumar0116
1

Answer:

V 入 RHZ2 1/n²1 - / n2

V max = 1/入min

=RH n1 =  RH

= 10967700m 1

入min = 91.2 nm for the series limit

First line is obtained when

n2 =

1/入= RH × 0.75

入=121.6nm

Explanation:

V 入 RHZ2 1/n²1 - / n2

V max = 1/入min

=RH n1 =  RH

= 10967700m 1

入min = 91.2 nm for the series limit

First line is obtained when n2 =

1/入= RH × 0.7

入=121.6nm

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm).

The energy needed to promote one electron in one atom from the 1-level to the point of ionisation may be determined using the frequency of the Lyman series limit. It is therefore possible to determine the ionisation energy per mole of atoms using this energy.

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