Chemistry, asked by harshiaharsh5, 1 month ago

calculate the wavelength and frequency of radiation emitted when an electron jumps from n≈3 to n≈1​

Answers

Answered by manishadhiman31
1

Answer:

vˉ=RH[n121]

vˉ=109677 cm−1[221−321]

⇒vˉ=109677×365=1523.9 cm−1

vˉ=λ1⇒λ=vˉ1=1523.91=6564×10−5cm

λ=6564×10−7m

E=λhc=6564×10−76.626×10−34×3×108

=3.028×1

Answered by majidalimondal46
2

Answer:

v

ˉ

=R

H

[

n

1

2

1

]

v

ˉ

=109677 cm

−1

[

2

2

1

3

2

1

]

v

ˉ

=109677×

36

5

=1523.9 cm

−1

v

ˉ

=

λ

1

⇒λ=

v

ˉ

1

=

1523.9

1

=6564×10

−5

cm

λ=6564×10

−7

m

E=

λ

hc

=

6564×10

−7

6.626×10

−34

×3×10

8

=3.028×10

−19

J

Similar questions