calculate the wavelength and frequency of radiation emitted when an electron jumps from n≈3 to n≈1
Answers
Answered by
1
Answer:
vˉ=RH[n121]
vˉ=109677 cm−1[221−321]
⇒vˉ=109677×365=1523.9 cm−1
vˉ=λ1⇒λ=vˉ1=1523.91=6564×10−5cm
λ=6564×10−7m
E=λhc=6564×10−76.626×10−34×3×108
=3.028×1
Answered by
2
Answer:
v
ˉ
=R
H
[
n
1
2
1
]
v
ˉ
=109677 cm
−1
[
2
2
1
−
3
2
1
]
⇒
v
ˉ
=109677×
36
5
=1523.9 cm
−1
v
ˉ
=
λ
1
⇒λ=
v
ˉ
1
=
1523.9
1
=6564×10
−5
cm
λ=6564×10
−7
m
E=
λ
hc
=
6564×10
−7
6.626×10
−34
×3×10
8
=3.028×10
−19
J
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