calculate the wavelength associated with 1) 1mev electron 2) 1mev proton
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Answer:
W of electron = 5.76 ×10^-23
W of proton = 1.04× 10^-23
Explanation:it will depend on both proton and electron mass as
W=h/(2ME)^1/2
E=energy in ev
E=1mev= 10^6ev
Now,
Mass of proton = 1.6 ×10^-27kg
Mass of electron = 9.01 × 10^-31kg
W(electron)=
6.65 ×10^-34÷(2×9.01×10^-31×10^6)^1/2
=5.76×10^-23
W(proton)=
6.65×10^-34÷(2×1.6×10^-27×10^6)^1/2
=1.04×10^-23
I hope that this is the answer
If i am wrong then please let me know.
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