Question

Calculate the wavelength associated with a moving electron having kinetic energy of 1.375×10 to power minus 25 J . plz solve this systematic way​

Answer 1

Answer:

1.735

Explanation:

1.375 10*is the answer

Answer 2

Answer:

Given :-

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ J

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelength

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEh

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEhm = 9.31 × 10⁻³¹

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEhm = 9.31 × 10⁻³¹\sf :\implies \dfrac{6.62\times10^{-34}}{\sqrt{2\times9.31\times 10^{-31}\times 1.375\times 10^{-25}}}:⟹2×9.31×10−31×1.375×10−256.62×10−34

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEhm = 9.31 × 10⁻³¹\sf :\implies \dfrac{6.62\times10^{-34}}{\sqrt{2\times9.31\times 10^{-31}\times 1.375\times 10^{-25}}}:⟹2×9.31×10−31×1.375×10−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-31-25}}}:⟹25.6025×10−31−256.62×10−34

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEhm = 9.31 × 10⁻³¹\sf :\implies \dfrac{6.62\times10^{-34}}{\sqrt{2\times9.31\times 10^{-31}\times 1.375\times 10^{-25}}}:⟹2×9.31×10−31×1.375×10−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-31-25}}}:⟹25.6025×10−31−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-56}}}:⟹25.6025×10−566.62×10−34

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEhm = 9.31 × 10⁻³¹\sf :\implies \dfrac{6.62\times10^{-34}}{\sqrt{2\times9.31\times 10^{-31}\times 1.375\times 10^{-25}}}:⟹2×9.31×10−31×1.375×10−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-31-25}}}:⟹25.6025×10−31−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-56}}}:⟹25.6025×10−566.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{5.05\times10^{-40}}:⟹5.05×10−406.62×10−34

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEhm = 9.31 × 10⁻³¹\sf :\implies \dfrac{6.62\times10^{-34}}{\sqrt{2\times9.31\times 10^{-31}\times 1.375\times 10^{-25}}}:⟹2×9.31×10−31×1.375×10−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-31-25}}}:⟹25.6025×10−31−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-56}}}:⟹25.6025×10−566.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{5.05\times10^{-40}}:⟹5.05×10−406.62×10−34\sf :\implies \dfrac{6.62\times10^{-34}\times10^{40}}{5.05}:⟹5.056.62×10−34×1040

Given :-The Kinetic energy of 1.375 × 10⁻²⁵ JTo Find :-Calculate the wavelengthSolution :-We know that\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}λ=2×m×KEhm = 9.31 × 10⁻³¹\sf :\implies \dfrac{6.62\times10^{-34}}{\sqrt{2\times9.31\times 10^{-31}\times 1.375\times 10^{-25}}}:⟹2×9.31×10−31×1.375×10−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-31-25}}}:⟹25.6025×10−31−256.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-56}}}:⟹25.6025×10−566.62×10−34\sf :\implies \dfrac{6.62\times 10^{-34}}{5.05\times10^{-40}}:⟹5.05×10−406.62×10−34\sf :\implies \dfrac{6.62\times10^{-34}\times10^{40}}{5.05}:⟹5.056.62×10−34×1040\sf :\implies 1.31 \times 10^{-6}\; m:⟹1.31×10−6m