calculate the wavelength associated with a priton moving at 1 * 10^3 m/s
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Answer:
De-broglie wavelength -
\lambda = \frac{h}{mv}= \frac{h}{p}
- wherein
where m is the mass of the particle
v its velocity
p its momentum
\lambda = \frac{h}{mv} = \frac{{6.63} \times {10^{-34}}} {{1.67} \times {10^{-27}} \times {10^3}}
=0.40 nm
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