Question

Calculate the wavelength associated with an electron it's momentum and speed when it is accelerated through a potential of 54 v

Answer 1

Answer:

we have the wavelength associated with the electron. using de- Broglie relation. lambda = h/p ….where p=momentum of electron and h=Planck’s constant. so, p = h/ lambda. the kinetic energy = p^2 /(2m) = (h^2/ lambda^2) . (1/2m) substituting the values of h , m and lambda as given

Explanation:

plz mark as brailsit plzzz