Question

Calculate the wavelength associated with an electron raised to a potential 1600 V.​

Answer 1

Answer:

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Answer 2

Answer:

The wavelength associated with the electron is 0.03nm.

Explanation:

The wavelength associated with an electron is given as,

$\lambda=\frac{h}{\sqrt{2mqV} }$           (1)

Where,

λ=wavelength associated with an electron

h=planks constant=6.626×10⁻³⁴J/s

m=mass of the electron=9.1 ×10⁻³¹kg

q=charge on an electron=1.6×10⁻¹⁹C

V=potential through which the electron is accelerated

From the question we have,

V=1600V

By putting the required values in equation (1) we get;

$\lambda=\frac{6.626\times 10^-^3^4}{\sqrt{2\times 9.1 \times 10^-^3^1\times 1.6\times 10^-^1^9\times 1600} }=0.03nm$

Hence, the wavelength associated with the electron is 0.03nm.